What is the difference of this two list in python:
list1 = [1,2,3,4,5,6,7,8,9]
list2 = [[[[1,2,3,4,5,6,7,8,9]]]]
When I use type(list1) and type(list2), all come with list , but when I try to make some deal such as:
Using list1:
new_total=[]
for i in range(0,len(list1),3):
b=list1[i:i+3]
print(len(b))
output:
9
6
3
Using list2:
for i in range(0,len(list2),3):
b=list2[i:i+3]
print(len(b))
output:
1
Well the elements within list 2 are the first element of the list within a list within a list.
So they are both of type list, however in the first you are printing the length of three indexed values hence 3.
In the second for loop you are printing the length of the inner list within a list, that only has one element in it (another list, which contains a list that contains the list of numbers within that)
Basically you have embedded the list of numbers 4 fold as the first element within the original list
replying for only to clarify these reponses , just to help you to understand (as a friend) , i'll give some exemples, that may help you:
list1 = [1,2,3,4,5,6,7,8,9]
list2 = [[[[1,2,3,4,5,6,7,8,9]]]]
print (list2[0][0][0][0])
print (list2[0][0][0])
print (list2[0][0])
print (list2[0])
print (list2)
Output:
1
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[[1, 2, 3, 4, 5, 6, 7, 8, 9]]
[[[1, 2, 3, 4, 5, 6, 7, 8, 9]]]
[[[[1, 2, 3, 4, 5, 6, 7, 8, 9]]]]
I hope that's clear. Good luck!
list1 = [1,2,3,4,5,6,7,8,9]
list2 = [[[[1,2,3,4,5,6,7,8,9]]]]
list1 is a list.
list2 is a list of list of list of list.
len(list1) #will get you 9.
len(list2) #will get you 1.
You will either have to iterate into the final list inside list2 or somehow flatten it into a one dimensional list. Hope this helps point you in the right direction without directly giving out the answer.
3 3 3.