package main
import "fmt"
type Employee struct {
ID int
Name string
}
func main(){
var zhexiao Employee
zhexiao.Name = "xiao"
fmt.Println(&zhexiao)
x := 1
p := &x
fmt.Println(p)
}
The above code outputs two kinds of pointers.
&{0 xiao}0xc0420600b0 (it looks like a memory address)Why struct pointer output is not a memory address? If it's not memory address, what is it?
Thanks a lot Zhe
It depends on how you look at it. You are implicitly using the package fmt default print verb (%v). Here are some other ways to look at it by explicitly using other print verbs.
package main
import "fmt"
type Employee struct {
ID int
Name string
}
func main() {
var zhexiao Employee
zhexiao.Name = "xiao"
fmt.Printf("%[1]v %[1]p\n", &zhexiao)
x := 1
fmt.Printf("%[1]v %[2]p\n", x, &x)
p := &x
fmt.Printf("%[1]v %[1]p\n", p)
}
Playground: https://play.golang.org/p/4dV8HtiS8rP
Output:
&{0 xiao} 0x1040a0d0
1 0x1041402c
0x1041402c 0x1041402c
Reference: Package fmt: Printing
