Windows Service relative path issue in Python

Question

I have written a small Windows Service compiled to an exe using py2exe, which from I read a file. It works great - however - I can only use an absolute path to access the file, using a relative path won't work. In .net you can do something like:

System.Reflection.Assembly.GetEntryAssembly().Location

To get the path to the .exe file, is there an option similar to this but for Python?

Best Regards,

Anders

Nick Bastin · Accepted Answer · 2011-02-25 12:38:02Z

1

You have a couple of options. If you already have a module object, you can do <module>.__file__ to get the path:

>>> import time
>>> time.__file__
'/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/lib-dynload/time.so'

However, often times you want to know the location of your current module, in which case you can use:

import inspect

path = inspect.currentframe().f_code.co_filename

(Also keep in mind that this can be anything that can be loaded by Python - so it can be a .pyd, .pyc, .so, .dll, etc.)

answered Feb 25, 2011 at 12:38

Nick Bastin

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2 Comments

Nick Bastin Over a year ago

@martineau: They both work, it's just a question of what you have as input. If you're in the module whose code you want to locate, you have to use the second one.

Anders Over a year ago

I looked at a standard module in python, for example, json used the first example, then did a split on .exe since that is included in the path. And everything before that is the relative path.

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