Extracting part of variable name for use in function

Question

I have an object, res_list, that contains data that I would like to extract using a function.

res_list$ has the following possibilities: Cearly,Rearly,Clate,Rlate,Cfollow,Rfollow.

I want to create a function to extract data from all the different res_list$ possibilities, in an iterative manner, by utilising the 'name' of data objects I have already created in R

The names of these objects are as follows:

signi_BTM_Cearly2
signi_BTM_Clate2
.
.
.
signi_BTM_Rfollow2

Basically, I just want to tell the function I am creating to take only the "Cearly", "Clate",..."Rfollow" part of the table names. So I can retrieve the data that I need.

I know its a very simple task, I just can't figure it out.

Thank you all for your time,

Try to wrap your samples in CODE TAGS {} button and try to select any one of the answer as correct answer to complete any thread, cheers and happy learning. — RavinderSingh13
– RavinderSingh13, Commented Jul 11, 2018 at 17:28

RavinderSingh13 · Accepted Answer · 2018-07-11 17:19:44Z

1

Following simple use of gsub may also help you here.

val3<-c("signi_BTM_Cearly2","signi_BTM_Clate2")
gsub(".*_|\\d+$","",val3)

Output will be as follows.

[1] "Cearly2" "Clate2"

edited Jul 11, 2018 at 17:19

answered Jul 11, 2018 at 17:17

RavinderSingh13

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2 Comments

akrun Over a year ago

I think you need gsub(".*_|\\d+$", "", val3)

RavinderSingh13 Over a year ago

@akrun, ahh missed it, thanks for letting me know sir you ROCK, changed it now.

akrun · Accepted Answer · 2018-07-11 16:44:10Z

0

We could use sub to capture the characters after the _ as a group followed by one or more digits (\\d+) at the end ($) of the string and replace by the backreference (\\1) of the captured group

sub(".*_([A-Za-z]+)\\d+$", "\\1", str1)
#[1] "Cearly"  "Clate"   "Rfollow"

data

str1 <- c("signi_BTM_Cearly2", "signi_BTM_Clate2", "signi_BTM_Rfollow2")

answered Jul 11, 2018 at 16:44

akrun

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