How to call CreateApiView and ListApiView using same url conf in django-rest-framework?

Question

I am trying to build a GET and POST method to get and save some objects. I have views.py like this

class QuestionList(generics.ListAPIView):
    queryset = Question.objects.all()
    serializer_class = QuestionSerializer

class QuestionSave(generics.CreateAPIView):
    queryset = Question.objects.all()
    serializer_class = QuestionSerializer

Then I have url conf, urls.py like this

urlpatterns = [
    url(r'^questions/$',views.QuestionList.as_view())
    ]

In my understanding, we have to have a generic class with CreateApiView for POST methods and ListApiView for GET method and so I have created classes like that. My question is, how should I configure them so that on POST QuestionSave will be called and on GET QuestionList will be called?

why not QuestionList(generics.ListAPIView, generics.CreateAPIView)? — user8060120
– user8060120, Commented Jul 26, 2018 at 11:37

Mehak · Accepted Answer · 2018-07-26 11:45:25Z

3

Use ListCreateAPIView. It provides get and post method handlers for a view.

Refer: Django Rest Framework

class QuestionView(generics.ListCreateAPIView)
    queryset = Question.objects.all()
    serializer_class = QuestionSerializer

edited Jul 26, 2018 at 11:45

answered Jul 26, 2018 at 11:42

Mehak

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3 Comments

theanilpaudel Over a year ago

thanks for the answer and it worked but now I am getting 'this field is required' error. Can you help me on this one as well?

Mehak Over a year ago

Sure. Post the code for your model's serializer and model

Mehak Over a year ago

The error for 'this field is required' is raised when you're not sending a particular field in post request, but it is required in your model or serializer.

Adelina · Accepted Answer · 2018-07-26 11:37:18Z

2

Simple!:

class QuestionList(generics.ListAPIView, generics.CreateAPIView):
    queryset = Question.objects.all()
    serializer_class = QuestionSerializer

answered Jul 26, 2018 at 11:37

Adelina

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