Redux call function and dispatch type in same function

Question

I have a redux actions for sessiontimeout and logout. When Sessiontimeout called, Internally calling the logout function.

It did not work also SESSIONTIMEOUT action type not dispatched.

How I suppose to call logout in Sessiontimeout and dispatch both SESSIONTIMEOUT and LOGOUT

export function sessionTimeOut(){
    return (dispatch) => {
    dispatch({
        type: ACTIONTYPES.SESSIONTIMEOUT
    })
    }
    logout()
}

export function logout(){
    history.push('/')
    return { 
        type: ACTIONTYPES.LOGOUT 
    }
}

CodeZombie · Accepted Answer · 2018-07-26 13:35:19Z

1

Just dispatch logout() right after the SESSIONTIMEOUT action.

  export function sessionTimeOut(){
        return (dispatch) => {
        dispatch({
            type: ACTIONTYPES.SESSIONTIMEOUT
        });
        dispatch(logout());
        } 
    }

answered Jul 26, 2018 at 13:35

CodeZombie

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