Compare URLs from two different text files Python

Question

I have a text file (links.txt) in the following format:

www.independent.co.uk www.bbc.co.uk www.theguardian.com www.telegraph.co.uk 
www.dailymail.co.uk en.wikipedia.org www.huffingtonpost.co.uk www.bbc.co.uk 
www.newsnow.co.uk www.express.co.uk

I have another text file (keys.txt) in the following format:

www.independent.co.uk www.bbc.co.uk www.theguardian.com

I want to compare both the text files and the URLs that are common in both the files has to be printed

I tried using the urltools package in python but couldn't do it for multiple urls

Those two files seem to be the same "format", ie a space-separated list of domains. What is the difference between them? — Daniel Roseman
– Daniel Roseman, Commented Aug 3, 2018 at 17:41
Yes, they are in the same format. I want to see if the urls in keys.txt are existing in links.txt. If they exist then it has to print that specific url. — clawstack
– clawstack, Commented Aug 3, 2018 at 17:43
I used urltools.compare which compares 2 urls and tells whether they match or not. — clawstack
– clawstack, Commented Aug 3, 2018 at 17:45

agillgilla · Accepted Answer · 2018-08-03 17:42:36Z

1

How about this:

links = open('links.txt', 'r')
links_data = links.read()
links.close()

keys = open('keys.txt', 'r')
keys_data = keys.read()
keys.close()

keys_split = keys_data.split()

for url in keys_split:
    if url in links_data:
        print(url)

Just make sure that links.txt and keys.txt are in the current working directory and everything should work fine. I'm assuming your URLs will always be space-delimited.

answered Aug 3, 2018 at 17:42

agillgilla

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2 Comments

clawstack Over a year ago

Yes, this is what I was looking for. Thanks! @agillgilla

agillgilla Over a year ago

No problem. Please mark it as the accepted answer if it answered your question @clawstack.

Puneet · Accepted Answer · 2022-08-19 05:00:21Z

0

To print only unique URL instead common URL, just modify condition not in, here is complete code -

links = open('links.txt', 'r')
links_data = links.read()
links.close()

keys = open('keys.txt', 'r')
keys_data = keys.read()
keys.close()

keys_split = keys_data.split()

for url in keys_split:
    if url not in links_data:
        print(url)

answered Aug 19, 2022 at 5:00

Puneet

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