Swift: Order array with same values

Question

I have a 2D array with multiples values.

One field on this array is called group, let's imagine my array have this order:

private var myArray = [
   ArrayModel(
      id: 0,
      name: "Test",
      color: 0,
      img: "img.png",
      group = "myGroup"),
   ArrayModel(
      id: 1,
      name: "Test1",
      color: 0,
      img: "img.png",
      group: "myGroup"),
   ArrayModel(
      id: 2,
      name: "Test2",
      color = 0,
      img = "img.png",
      group = "myGroup3")
   ArrayModel(
      id: 3,
      name: "Test3",
      color: 0,
      img: "img.png",
      group: "myGroup2"),
   ArrayModel(
      id: 4
      name: "Test4"
      color: 0
      img: "img.png"
      group: "myGroup3")
]

Array Model

class ArrayModel: Decodable {

var id: Int
var name: String
var color: Int
var img: String
var group: String

convenience init() {
    self.init()
    id = 0
    name = ""
    color = 0
    img = ""
    group = ""
}

init(id: Int, name: String, color: Int, img: String, group: String) {
    self.id = id
    self.name = name
    self.color = color
    self.img = img
    self.group = group
}

}

How can I move my myArray[2] to be in myArray[1] ?

My desired output is :

let myArray = [
   ArrayModel(
      id: 0,
      name: "Test",
      color: 0,
      img: "img.png",
      group: "myGroup")
   ]
   [1] => same shema, but group => "myGroup"
   [2] => same shema, but group => "myGroup2"
   [3] => same shema, but group => "myGroup2"
   [4] => same shema, but group => "myGroup3"
]

I tried this :

myArray.sorted(by: { $0.group < $1.group })

Thanks for your help!

Please can you show your exact input and desired output? (as well as any code you've tried?) — Adi219
– Adi219, Commented Aug 8, 2018 at 8:49
It's not clear what you're asking - a (deleted) answer correctly showed how to move myArray[2] to myArray[1] — Ashley Mills
– Ashley Mills, Commented Aug 8, 2018 at 8:51
It is edited now. Sorry for the wrong formulation, it's a bit hard to explain myself on problems like this :-) — Romain Sickenberg
– Romain Sickenberg, Commented Aug 8, 2018 at 8:53
You say it's a 2D array but it looks more like an array of dictionaries or structs. Could you show us some real code instead of this pseudo code? — Joakim Danielson
– Joakim Danielson, Commented Aug 8, 2018 at 8:58
I've edited your question to show my understanding of what myArray initially looks like. Am I correct? (If not, feel free to roll back the edit) — Adi219
– Adi219, Commented Aug 8, 2018 at 8:59

Adi219 · Accepted Answer · 2018-08-08 09:22:28Z

1

Try this:

myArray.sort { $0.group < $1.group }

The .sort(by: ...) isn't what you need here, as you want to modify myArray (by sorting it). To do that, you have to omit the by:....

For more information, see this answer :)

edited Aug 8, 2018 at 9:22

answered Aug 8, 2018 at 9:08

Adi219

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6 Comments

Nirav D Over a year ago

This doesn't make sense sorted return sorted array its not mutable method

Nirav D Over a year ago

Check the apple doc developer.apple.com/documentation/swift/array/2296815-sorted it will return sorted array you need to store the result, sort is the mutating method developer.apple.com/documentation/swift/array/2296801-sort

Adi219 Over a year ago

@NiravD Please see stackoverflow.com/questions/24130026/…

Nirav D Over a year ago

If you check the answer it is using sort method not the sorted check apple doc

Adi219 Over a year ago

@NiravD Yep, you're right! What you've been saying makes sense. Edited my answer :)

|

Pranavan SP · Accepted Answer · 2018-08-08 09:25:03Z

1

This may help you to sorted by Case Sensitive but your myArray should be mutable. ex : var myArray

myArray = myArray.sorted(by: { $0.group.localizedCompare($1.group) == .orderedAscending})

edited Aug 8, 2018 at 9:25

answered Aug 8, 2018 at 9:07

Pranavan SP

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