I need to get a number, knock the last number off and then return it as a number
i.e. given the number 12345, return 1234
is this the best way to do it:
let x = 12345
const y = x.toString().split('').slice(0, -1).join('')
const newNum = Number(y)
also is there a way to not do the const newNum and then just convert it back to a number in the string above?
Here's another way to do it
console.log(
Math.floor(12345 / 10) // -> 1234
)
Math.floor(12345 / 10) or 12345 / 10 | 0 will end up with the same result. If someone doesn't understand that, they can look into it. That's how you learn about these things.Math.floor(12345 / 10), I thought it would be a bit overkill to introduce them to how bitwise operators work and how they convert floating point numbers to signed 32-bit integers . Also, because of that, it won't always give you the same result, it only works upto 2^31 − 1.Easy:
console.log(12345 / 10 ^ 0)You could refactor the code to this
let x = 12345
const newNum = Number(x.toString().slice(0, -1))
console.log(newNum)
Using parseInt() to convert back to number, and substring to get the entire number minus the last digit
return parseInt(x.toString().substring(0, x.toString().length - 1));
Put the number into brackets () to use .slice()
let x = 12345
const newNum = (x).toString().slice(0, -1)
console.log(newNum)
console.log(newNum * 1000)
Math.floor()