Pass variables to cURL in batch file

Question

I use a cURL command stored in .bat file.

I want to have variables implemented in the command, that will receive the value when I call the command to execute the .bat file.

Can anybody help with understading the syntax of:

Passing variables to batch file
Defining certain parts of the cURL command as variables (The parts in bold below)

Here is my cURL command (Parts in bold should be variables):

curl -k --user "usercode:" -d source="https://secure.4log.com/**431032**" https://api.pdfshift.io/v2/convert/ -d sandbox=true --output C:\Users\administrator\Desktop\**testpdf11**.pdf

so you want to run your batch as somebatchfile.bat param1 param2 etc? — user7818749
– user7818749, Commented Aug 27, 2018 at 12:02
Call the batch file with two arguments/parameters,BatchScript.cmd "431032" "testpdf11" where the script would receive 431032 as %~1 and testpdf11 as %~2! curl -k --user "usercode:" -d source="https://secure.4log.com/%~1" https://api.pdfshift.io/v2/convert/ -d sandbox=true --output C:\Users\administrator\Desktop\%~2.pdf — Compo
– Compo, Commented Aug 27, 2018 at 12:04
Possible duplicate of Get list of passed arguments in Windows batch script (.bat) — aschipfl
– aschipfl, Commented Aug 27, 2018 at 13:15

score 1 · Accepted Answer · 2018-08-27 13:08:41Z

1

If you want to send parameters you simply use:

curl %1 %2 %3

Each numeric value defines the position of the word after your batch.

so as a simple example, if you run only need to run something like:

mybatch.bat 1234 5678

That 1234 will be seen as %1 and 5678 will be %2 and you will get:

source="https://secure.4log.com/%1" C:\Users\administrator\Desktop\%2.pdf

resulting to:

source="https://secure.4log.com/1234" C:\Users\administrator\Desktop\5678.pdf

If you plan on using paramters with space, or any quoted text for that matter, you should rather use %~1 and %~2 as it will remove the quotes for you.

edited Aug 27, 2018 at 13:08

answered Aug 27, 2018 at 12:06

user7818749

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2 Comments

Yaniv Ben-Malka Over a year ago

IMPORTANT NOTE - It worked in the batch file only with a tilde ( %~1 and %~2) as @compo suggested in my original post comments

user7818749 Over a year ago

@YanivBen-Malka yes. I am aware. ~ simply removes double quotes. So if you use quoted input i.e paramters with a space, the you require the ~ simply test it by creating a test batch file and add code. echo %1 %~1 then call it as batchfile.bat "this line" and you will see it will echo "this line" this line

Stephan · Accepted Answer · 2018-08-27 14:44:33Z

1

Parameters to the batchfile are referenced by %1 for the first one, %2 for the second one and so on until %9 This makes your command:

curl -k --user "usercode:" -d source="https://secure.4log.com/%~1" https://api.pdfshift.io/v2/convert/ -d sandbox=true --output C:\Users\administrator\Desktop\%~2.pdf

Note: use %~1 to remove surrounding quotes (no effect, if there aren't such)

You might want to check if there are at least two parameters before with:

if "%~2"=="" (echo you need two parameters & goto :eof )

(Maybe even add some plausibility tests)

edited Aug 27, 2018 at 14:44

answered Aug 27, 2018 at 12:06

Stephan

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2 Comments

Yaniv Ben-Malka Over a year ago

IMPORTANT NOTE - It worked in the batch file only with a tilde ( %~1 and %~2) as @compo suggested in my original post comments

Stephan Over a year ago

The ~ is to remove surrounding quotes. You didn't mention quotes in your question.

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