I don't know if you consider this an important question or not but I want to know. float is a float number (4 bytes). double is a float number (8 bytes). Why we define double wihtout casting:
double d = 2.1;
But we need to cast with floats:
float f = (float) 2.1;
or
float f = 2.1f;
Thank you in advance.
By default, Java compiler perceives 2.1 as being a double (64 bits) and not as a float (32 bits). Declaring float f=2.1 would result in loss of precision. Hence, Java forces you to do the casting to make sure you are declaring a float variable.
Without casting, you can achieve the same with the letter 'f' at the end of floating point numbers. For example, float f=2.1f.
Now you might ask, why a cast isn't required while converting from a long to a float because the former uses more bits internally than the latter. The answer is Java needs no casting on a widening path - byte => short => int => long => float => double. (Left to right (a widening conversion) - cast is not required; Right to left (a narrowing conversion) - explicit cast is required)
float is wider than long it can have a lot less precision.A floating-point literal is of type float if it ends with the letter F or f; otherwise its type is double and it can optionally end with the letter D or d.
The floating point types (float and double) can also be expressed using E or e (for scientific notation), F or f (32-bit float literal) and D or d (64-bit double literal; this is the default and by convention is omitted).
double d1 = 123.4;
// same value as d1, but in scientific notation
double d2 = 1.234e2;
float f1 = 123.4f;
