Compiler error in Typescript version 3 but not in version 2

Question

Since updating Typescript to 3.x I can not compile this class anymore:

class MyClass<T>{
    private myMethods: [(val: T) => void] = [] as [(val: T) => void];
}

More specific, it is [] as [(val: T) => void] that triggers the error and the compiler message is:

Error:(7, 47) TS2352: Type '[]' cannot be converted to type '[(val: T) => void]'.
  Property '0' is missing in type '[]'.

It DO work in Typescript 2.9.2 though!

So what is the problem here and how do I solve it?

Probably a breaking change, although I can't find any documentation in 3.0 about it. Length was added to tuples a while ago so it's probably not because of that. Tuples were worked on in 3.0 so that might have something to do with it. The simplest solution is to asset to any or use [null] instead as that would be a valid value for your tuple with a single element — Titian Cernicova-Dragomir
– Titian Cernicova-Dragomir, Commented Aug 29, 2018 at 15:49

Akash Kava · Accepted Answer · 2018-08-29 17:02:25Z

1

This is due to tuple length enforcement in TypeScript 3.0 which forces signature [T] to have one element in the array of type T.

The only solution is to make an element type optional as follow.

class MyClass<T>{
    private myMethods: [((val: T) => void)?] = [] as [((val: T) => void)?];
}

answered Aug 29, 2018 at 17:02

Akash Kava

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Comments

Oblosys · Accepted Answer · 2018-08-29 20:29:00Z

1

If myMethods is not a tuple but an array (as the name suggests,) you can just do

class MyClass<T>{
    private myMethods: Array<(val: T) => void> = [];
}

answered Aug 29, 2018 at 20:29

Oblosys

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