As long as you don't mind some restrictions, this is fairly easy to do. The easiest way to do the job restricts you to classes that descend from one common base class. In this case, you can do something like this:
// warning: I've done this before, but none of this code is tested. The idea
// of the code works, but this probably has at least a few typos and such.
struct functor_base {
virtual bool operator()() = 0;
};
You'll then obviously need some concrete classes derived from that base:
struct eval_x : functor_base {
virtual bool operator()() { std::cout << "eval_x"; }
};
struct eval_y : functor_base {
virtual bool operator()() { std::cout << "eval_y"; }
};
Then we need some way to create an object of each type:
functor_base *create_eval_x() { return new eval_x; }
functor_base *create_eval_y() { return new eval_y; }
Finally, we need a map from the names to the factory functions:
// the second template parameter is:
// pointer to function returning `functor_base *` and taking no parameters.
std::map<std::string, functor_base *(*)()> name_mapper;
name_mapper["eval_x"] = create_eval_x;
name_mapper["eval_y"] = create_eval_y;
That (finally!) gives us enough so we can map from a name to a function object:
char *name = "eval_x";
// the map holds pointers to functions, so we need to invoke what it returns
// to get a pointer to a functor:
functor_base *b = name_mapper.find(name)();
// now we can execute the functor:
(*b)();
// since the object was created dynamically, we need to delete it when we're done:
delete b;
There are, of course, many variations on the general theme. For example, instead of factory functions that create objects dynamically, you can create an instance of each object statically, and just put the address of the static object in the map.