Dynamic Table Rows using XSLT and XML

Question

I'm very new to XSLT and XML. I'm trying to make a dynamic list based on how many CASES come back from an XML file.

The XML section about CASES looks like this:

...
<CASES>
    <CASE>000000000000014-00001</CASE>
    <CASE>000000000000014-00002</CASE>
    <CASE>000000000000014-00003</CASE>
</CASES>
...

My XSLT code (excerpt) for the table I'm creating looks like this:

...
CASES:
<table style="width: 100%;">
<xsl:for-each select="CASES/CASE">
    <tr>
        <td><xsl:value-of select="CASE"/></td>
    </tr>
</xsl:for-each>
</table>
...

The output is three blank table rows. Could you please tell me what I'm doing wrong?

kjhughes · Accepted Answer · 2018-08-31 00:22:04Z

1

Since your xsl:for-each loop alread selects CASE elements,

<xsl:for-each select="CASES/CASE">

your xsl:value-of shouldn't be

    <td><xsl:value-of select="CASE"/></td>

because that looks for a CASE child of the current CASE element.

Instead, within the loop just select the current element itself, available as .:

    <td><xsl:value-of select="."/></td>

answered Aug 31, 2018 at 0:22

kjhughes

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2 Comments

alcor8 Over a year ago

It worked. Thank you. It put them side by side. Any advice on how I can get them each in their own row?

kjhughes Over a year ago

Your shown XSLT snippet already has them in their own row by virtue of the <tr>...</tr> that wraps the single td elements within the CASE loop.

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