is it possible to use the multiple cases in "if condition" to access the same function

Question

I need to access the same function for all the cases so I implemented the multiple cases in the if condition. as IDE Throws an error for this, it is obvious that this is the wrong implementation. But is there something which can be an alternative to such logic.

java

 void movie() {
                int m;
                System.out.println("Choose the movie :");
                System.out.println("1.BAHUBALI\n2.SHIVAAY\n3.DANGAL\n4.AIRLIFT");
                m =sc.nextInt();
          switch(m){
                if(case 1: || case 2: || case 3: || case 4:) {
                     Payment();
                }

                else {
                    System.out.println("Choosen an Invlid option");
                }
            }
        }

Do take a look at rephrased switch labels...

Naman
– Naman

2018-09-08 18:34:13 +00:00
Commented Sep 8, 2018 at 18:34 — Naman
– Naman, Commented Sep 8, 2018 at 18:34

vinay chhabra · Accepted Answer · 2018-09-01 03:35:55Z

7

Try this:-

switch (key) {
        case 1:
        case 2:
        case 3:
        case 4: 
            Payment();
            break;

        default:
            System.out.println("Choosen an Invlid option");
            break;
        }

answered Sep 1, 2018 at 3:35

vinay chhabra

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Comments

Ashishkumar Singh · Accepted Answer · 2018-09-07 03:13:48Z

0

Since you are doing Integer comparison here, you could use Map to reduce the comparison to only one condition. Something like below

    Map<String, Integer> map = new HashMap<>();
    map.put("1", 1);
    map.put("2", 2);
    map.put("3", 3);
    map.put("4", 4);

    void movie() {
    int m;
    System.out.println("Choose the movie :");
    System.out.println("1.BAHUBALI\n2.SHIVAAY\n3.DANGAL\n4.AIRLIFT");
    m = sc.nextInt();

    if (map.containsKey(m)) {
        Payment();
    }
    else {
        System.out.println("Choosen an Invlid option");
    }
}

Map.containsKey : Returns true if this map contains a mapping for the specified key.

So, initially we are putting the value that we are expecting from the user in Map object and then, checking if the actual user input is present in the object using containsKey. If it is then call, Payment() else, println some message

edited Sep 7, 2018 at 3:13

answered Sep 1, 2018 at 3:51

Ashishkumar Singh

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2 Comments

Aniket Jadhav Over a year ago

can you explain shortly?

Ashishkumar Singh Over a year ago

@AniketJadhav Updated my answer. Kindly have a look

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