PHP Check variable that contains null as string

Question

I'm checking whether to enter an if statement and debugging the result of a function it turn out that it returns null as a string.

In my code I'm checking:

<?php if($_product->getData('attr1') || $_product->getData('attr2')): ?>
      Do stuf here
<?php endif; ?>

And 'attr2' returns 'null', a string with length equals to 4.

How can I check if the variable is null for real?

Is your problem that getData() returns 'null' instead of null? Handle it there. — simPod
– simPod, Commented Sep 8, 2018 at 9:11
@simPod yes the problem is that, isn't there a way to check here in my template that the variable is null instead of 'null'? — Alessio
– Alessio, Commented Sep 8, 2018 at 9:12
You'd probably have to add a condition to check for 'null'. IMO the proper way to handle this is to fix getData method to return null. It will ease your pain in all places where you use it then. Because what if attr2 has really a 'null' value? — simPod
– simPod, Commented Sep 8, 2018 at 9:14
@simPod is saying absolute right, you need to add another string comparison for 'null' value. — Niklesh Raut
– Niklesh Raut, Commented Sep 8, 2018 at 9:19

Niklesh Raut · Accepted Answer · 2018-09-08 09:17:45Z

1

'null' is a string value that's why it is passing your checks. you need to check it like string value as well.

<?php if($_product->getData('attr1') || ($_product->getData('attr2') && strtolower($_product->getData('attr2')) != 'null' ) ): ?>
      Do stuf here
<?php endif; ?>

It is case specific, if you have 'null', 'Null' or NULL string for only attr2

answered Sep 8, 2018 at 9:17

Niklesh Raut

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