How to get a current date for upload_to in Django models

Question

Since some image files have name conflicts, I decided to make the system to change a uploaded file's name automatically. However, after changing the system, I got in trouble with getting a current date for the file path.

This is how my previous Image model looks like, and it stores an image with a name like boutique/index/2018/9/20/FILE_NAME.jpg.

class Image(TimeStampedModel):
    ...
    image = ImageField(..., upload_to='boutique/index/index/%Y/%m/%d')
    ...

After that, I changed it to like this. This successfully changes a uploaded image's name automatically. However, it stores a name like boutique/%Y/%m/%d/FILE_NAME.jpg.

def image_path(instance, filename):
    basefilename, file_extension = os.path.splitext(filename)
    chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890'
    randomstr = ''.join((random.choice(chars)) for x in range(10))
    return 'boutique/index/%Y/%m/%d/{imageid}/{basename}{randomstring}{ext}'.format(imageid=instance.store.domainKey, basename=basefilename, randomstring=randomstr, ext=file_extension)

class Image(TimeStampedModel):
    ...
    image = ImageField(..., upload_to=image_path)
    ...

Like you see the above, the problem is that %Y, %m, and %d don't provide date data I need anymore. What is wrong here? image_path function returns the same thing in the same place. I don't know why they are just like recognized as a normal string

You can use epoch time or combination of epoch time and user id to avoid name conflicts. Or is there any specific reason to use this pattern. — Abhijith Konnayil
– Abhijith Konnayil, Commented Sep 20, 2018 at 20:06

juanmhidalgo · Accepted Answer · 2018-09-20 19:34:40Z

3

You have to set those values manually.

Add the import

from datetime import datetime

And replace in your function %Y, %m, %d with {year}, {month}, {day} variables and add the values to the format call.

def image_path(instance, filename):
    basefilename, file_extension = os.path.splitext(filename)
    chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890'
    randomstr = ''.join((random.choice(chars)) for x in range(10))
    _now = datetime.now()

    return 'boutique/index/{year}/{month}/{day}/{imageid}/{basename}{randomstring}{ext}'.format(
        imageid=instance.store.domainKey, 
        basename=basefilename, randomstring=randomstr, ext=file_extension,
        year=_now.strftime('%Y'), month=_now.strftime('%m'), day=_now.strftime('%d')
        )

More about file uploads in django

answered Sep 20, 2018 at 19:34

juanmhidalgo

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