How can use Try/Catch in Python

Question

I want use try...catch in Python but Python give me an error what's can I do?

try:
    input('enter your number');
catch:
    print('please give integer');

except is mostly explained using the words "catch exceptions" in the docs and hence I guess you used the word catch ;) — Sheldore
– Sheldore, Commented Sep 21, 2018 at 10:43

Abdi · Accepted Answer · 2018-09-21 10:43:58Z

7

try/catch in python is try/except.

you can use try/except like this:

try:
   input('enter your number');
except expression:
   print('please give integer');

answered Sep 21, 2018 at 10:43

Abdi

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2 Comments

Vineeth Sai Over a year ago

What is the expression here?

fatih Over a year ago

nice semi comma use there :)

Vineeth Sai · Accepted Answer · 2018-09-21 11:56:26Z

5

try: 
    int(input('enter your number')); 
except ValueError: 
    print('please give integer');

Use handling-exceptions

edited Sep 21, 2018 at 11:56

Vineeth Sai

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answered Sep 21, 2018 at 10:51

Umesh Yadav

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Comments

awakened_iota · Accepted Answer · 2018-09-21 10:56:19Z

1

You can use following alternative for your use case :

try:
    input_ = int(input('enter your number'))
except:
    print('please give integer')
    exit() #if you want to exit if exception raised
#If no exception raised, execution continues from here
print(input_)

answered Sep 21, 2018 at 10:56

awakened_iota

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