How to check if a button is disabled using css in selenium webdriver [duplicate]

You can check if the element has disabled attribute. If it exists you will get String results, if not you will get null

WebElement button = driver.findElement(locator);
bool isDisabled = button.getAttribute("disabled") != null;

There are two way to check if the button is disabled as follows:

• Using try-catch{}:

  try {
      //css
      driver.findElement(By.cssSelector("fieldset.checkbox button.calvary-button[disabled]"));
      //xpath
      //driver.findElement(By.xpath("//button[@class='calvary-button' and contains(.,'Continue')][@disabled]"));
      System.out.println("Button is disabled");
  } catch (NoSuchElementException e) {
      System.out.println("Button is enabled");
  }
  

• Using findElements() and and assert zero length response:

  if(driver.findElements(By.cssSelector("fieldset.checkbox button.calvary-button[disabled]")).size()>0)
      System.out.println("Button is disabled");
  else
      System.out.println("Button is enabled");