I am getting an error when trying to run this code
In function 'int main()':
error: 'area' was not declared in this scope
I cannot find a clear solution to the problem.
#include <iostream>
using namespace std;
int main() {
area(13.3, 67.4);
return 0;
}
void area(int a, int b){
cout << "The area is " << a * b << endl;
}
void area(float a, float b){
cout << "The area is " << a * b << endl;
}
void area(double a, double b){
cout << "The area is " << a * b << endl;
}
You need to declare the functions before you can use them.
Either forward declare them:
#include <iostream>
using namespace std;
// forward declarations
void area(int a, int b);
void area(float a, float b);
void area(double a, double b);
int main() {
area(13.3, 67.4);
return 0;
}
void area(int a, int b){
cout << "The area is " << a * b << endl;
}
void area(float a, float b){
cout << "The area is " << a * b << endl;
}
void area(double a, double b){
cout << "The area is " << a * b << endl;
}
Otherwise, move the implementations above main():
#include <iostream>
using namespace std;
void area(int a, int b){
cout << "The area is " << a * b << endl;
}
void area(float a, float b){
cout << "The area is " << a * b << endl;
}
void area(double a, double b){
cout << "The area is " << a * b << endl;
}
int main() {
area(13.3, 67.4);
return 0;
}
That being said, since the implementations are exactly the same, just with different data types, consider using a single templated function instead:
#include <iostream>
using namespace std;
template<typename T>
void area(T a, T b){
cout << "The area is " << a * b << endl;
}
int main() {
area<double>(13.3, 67.4);
return 0;
}
Put functions prototypes above your main function and you should be fine.
