Call method from current Java context

Question

Currently I'm sending a text message from Android using the SmsManager and its working fine.

But I do want to listen to the Intent result and take some actions based on that, the following code was supposed to work, but I'm getting getResultCode as undefined on the runtime (But it works on the debugging console)

app.android.registerBroadcastReceiver(this.id, () => {
        if(this.getResultCode() == android.app.Activity.RESULT_OK){
            // Sucess
        } else {
            // Failure
        }
    });

How do I get the value from the getResultCode method properly ?

Brad Martin · Accepted Answer · 2018-10-01 14:55:32Z

1

You'll want to use the application module which exposes the android context.

https://docs.nativescript.org/api-reference/classes/application.androidapplication#context

EDIT

import * as app from 'tns-core-modules/application';

// then below is the Android context object
app.android.context;

edited Oct 1, 2018 at 14:55

answered Sep 28, 2018 at 4:07

Brad Martin

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3 Comments

André Roggeri Campos Over a year ago

Can you please expand how to do that ? Right now I fixed the problem by moving from arrow function to a standard function. This way I can access the correct context from JS.

Brad Martin Over a year ago

I wouldn't guess that would fix your problem. I believe you were wanting the Android Context, which is what the application module exposes a reference to. You're still using this in javascript. Unless you're using the Static Binding Generator to extend a native class here.

Brad Martin Over a year ago

Now that I looked over what you're doing, I was wrong. what you're doing makes more sense now.

André Roggeri Campos · Accepted Answer · 2018-10-17 23:58:54Z

0

I was using the arrow function, thus getting the wrong context.

Changing from arrow function to a standard function fixed the problem

app.android.registerBroadcastReceiver(this.id, function(){
        if(this.getResultCode() == android.app.Activity.RESULT_OK){
            // Sucess
        } else {
            // Failure
        }
    });

answered Oct 17, 2018 at 23:58

André Roggeri Campos

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