Iterating lists in django template

Question

I have different lists

context = {
    'query' : request.POST['query'],
    'link' : link,
    'description' : description,
    'title' : title,
    'thumbnail' : thumb,
    'range' : range(len(title)),
}

And I want to iterate through them something like:

for i in range(20):
    link[i]
    title[i]

In django template. How can i do it?

What are link and title here?

Kasravnd
– Kasravnd

2018-09-30 13:19:32 +00:00
Commented Sep 30, 2018 at 13:19 — Kasravnd
– Kasravnd, Commented Sep 30, 2018 at 13:19

user2390182 · Accepted Answer · 2018-09-30 13:27:27Z

2

You are probably better off creating those link-title pairs in your view where you have the full Python arsenal (e.g. zip) at your disposal:

context = {
    'link' : link,
    'title' : title,
    'link_title': list(zip(link, title)),
    # ...
}

You can slice that convenience list in the template if necessary:

{% for l, t in link_title|slice:":20" %}
    # do stuff with l, t
{% endfor %}

edited Sep 30, 2018 at 13:27

answered Sep 30, 2018 at 13:23

user2390182

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willeM_ Van Onsem · Accepted Answer · 2018-09-30 13:25:10Z

You normally don't typically you use a zip construct in the view, and then iterate concurrently over both (or more) iterators:

context = {
    'query' : request.POST['query'],
    'linktitle' : zip(link, title),
    'description' : description,
    'thumbnail' : thumb,
    'range' : range(len(title)),
}

and then in the template:

{% for linki, titlei in linktitle %}
   {{ linki }} / {{ titlei }}
{% endfor %}

If you are only interested in the first 20 elements, you can add a range(20) in the zip, or use islice:

from itertools import islice

context = {
    'query' : request.POST['query'],
    'linktitle' : islice(zip(link, title), 20),
    'description' : description,
    'thumbnail' : thumb,
    'range' : range(len(title)),
}

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