Calculate ISO 8601 time format to hours/minutes from now with Python

Question

How would I receive an input of a string (time in ISO 8601 format) and convert/calculate the duration from then until now?

Input: 2018-09-29T00:33:33Z

Output: 3 days ago

Thanks.

Dodge · Accepted Answer · 2018-10-02 13:51:56Z

2

from datetime import datetime
import dateutil.parser

a = datetime.now()
#a = datetime.strftime(a, format="%Y-%m-%d%H:%M:%S")
#a = a[:10] + 'T' + a[10:] + 'Z'
a = datetime.strftime(a, format="%Y-%m-%dT%H:%M:%SZ")

a = dateutil.parser.parse(a) - dateutil.parser.parse("2018-09-29T00:33:33Z")
print(str(a))

3 days, 2:00:00

edited Oct 2, 2018 at 13:51

answered Oct 2, 2018 at 2:19

Dodge

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1 Comment

Christian König Over a year ago

Why the string concatenation, when you use a format string before? Shouldn't a = datetime.strftime(a, format="%Y-%m-%dT%H:%M:%SZ") work?

xrisk · Accepted Answer · 2018-10-02 05:19:50Z

0

An easier solution using Arrow.

>>> import arrow
>>> d = arrow.get("2018-09-29T00:33:33Z")
>>> d.humanize()
'3 days ago'

answered Oct 2, 2018 at 5:19

xrisk

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