I have this string:
{"level": "INFO", "message": "89532154: phone number saved successfully."}
I wanted to extract just the word INFO out.
I have tried ^(\{.{10})(\w*), (?<="level":\s*)"(\w*)"
Other expressions that I have tried doesn't work.
So far, only .* works in Android Studio.
I'm using Android Studio 3.2
This is actually a JSON:
{
"level": "INFO",
"message": "89532154: phone number saved successfully."
}
You should be able to get the INFO like this from level:
JSONObject obj = new JSONObject(yourcurrentjson);
String levelOutput = obj.getString("level");
// level output should return the INFO
And this with regex:
Map<String, Integer> map = new HashMap<>();
for (String keyValue: json.split(",")) {
String[] data = keyValue.split(":");
map.put(
data[0].replace("\"", """),
Integer.valueOf(data[1].trim());
);
}
And then: map.get(key) for getting integers and this:
String.format("\"%s\"\\s*:\\s*\"((?=[ -~])[^\"]+)\"", id_field)
For getting strings like in your case.
Check this out: https://stackoverflow.com/a/37828403/4409113
In your first regex you match INFO in the second capturing group by matching first 10 times any character in the first capturing group.
For as far as I know, Java does not allow a variable length in the lookbehind, so \s* does not work. Instead you could use a quantifier like \\s{0,10}
In this case you are better off using a json parser but if you must use a regex you might use:
(?<=\\{\"level\":\\s{0,10}\")\\w+(?=\")
