Bash joining array

Question

Is there a way to join (with proper quoting and escaping) a bash array such that it gives me a string suitable for passing to bash -c?

Reason: I want to write a function foo, such that when I do this:

foo app "hello world.txt"

it'll do this:

sudo -u myuser ENVVAR=somevalue bash -c "perl app \"hello world.txt\""

choroba · Accepted Answer · 2018-10-11 08:34:14Z

1

bash -c takes the first argument as the command string, and assigns the remaining arguments to positional arguments starting from $0. So, you don't need to quote anything, just pass the arguments:

function foo () {
    sudo -u myuser ENVVAR=somevalue bash -c 'perl "$0" "$@"' "$@"
}

edited Oct 11, 2018 at 8:34

answered Oct 11, 2018 at 8:28

choroba

245k27 gold badges221 silver badges304 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Bash joining array

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related