Selecting class name in Python with Selenium

Question

I'm trying to click in the area 5 pixels below a class name on a web page.

This is the code :

homeLink = driver.find_element_by_class_name('*****')
action = webdriver.common.action_chains.ActionChains(driver)
action.move_to_element_with_offset(homeLink, 0, 5) 
action.click()
action.perform()

The error: "Message: no such element: Unable to locate element: {"method":"class name","selector":"*****"}"

The html:

<div class="*****">Internal Tags</div>

Try to implement Wait or check if element located inside an iframe — Andersson
– Andersson, Commented Oct 11, 2018 at 18:04
What is *****? Normally, in HTML, the class attribute is a space-separated list of classes, and the method find_element_by_class_name() takes one of those classes. — SiKing
– SiKing, Commented Oct 11, 2018 at 18:59

Ishita Shah · Accepted Answer · 2018-10-12 05:16:25Z

1

You may refer this,

homeLink = driver.find_element_by_xpath("//div[@class='*****' and contains(text(),'Internal Tags')]")
action=ActionChains(driver)
action.move_to_element(homeLink).click().perform()

answered Oct 12, 2018 at 5:16

Ishita Shah

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