PHP - replace http with https in URL

Question

I am trying to figure out how to add s after HTTP once a user checks a box in the html form.

I have in my PHP,

$url = 'http://google.com';

if(!isset($_POST['https'])) { 
  //something here
}

So basically, when the user checks a box with the name="https" i want to add s to $url's http making it https://google.com.

I have little knowledge on PHP and if someone can explain to me how to go about doing this, this would be really helpful! thanks.

Jakub Hampl · Accepted Answer · 2014-04-25 22:27:47Z

82

$url = preg_replace("/^http:/i", "https:", $url);

edited Apr 25, 2014 at 22:27

answered Mar 13, 2011 at 12:19

Jakub Hampl

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3 Comments

Nabi K.A.Z. Over a year ago

good solution, but it is better for incase-sensitive: $url = preg_replace("/^http:/i", "https:", $url);

Mimouni Over a year ago

i tested this solution, unfortunatly this was not working, i tried next solution with "str_replace" and get the result.

Cacoon Over a year ago

str_replace didnt work for me, but the original did. Also many thanks for this great solution, saved a giant issue with a wordpress theme im customizing that would otherwise force mixed content over SSL and break SSL connection.

tivnet · Accepted Answer · 2013-12-11 13:11:33Z

16

$url = str_replace( 'http://', 'https://', $url );

answered Dec 11, 2013 at 13:11

tivnet

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Comments

Felix Kling · Accepted Answer · 2011-03-13 12:18:47Z

2

One way:

$url = '%s//google.com';
$protocol = 'http:';

if(!isset($_POST['https'])) { 
    $protocol = 'https:';
}

$url = sprintf($url, $protocol);

answered Mar 13, 2011 at 12:18

Felix Kling

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1 Comment

Kevin Jung Over a year ago

thanks for the code but I can't break up the $url because it is being used in a previous function which requires the entire url. Would there be another way of doing it?

Rodgath · Accepted Answer · 2019-04-03 02:23:12Z

When you consider case-insensitive, then use str_ireplace function.

Example:

$url = str_ireplace( 'http://', 'https://', $url );

Alternatively, incase you ant to replace URL scheme in CDN files. Example:

$url = str_ireplace( 'http:', 'https:', $url );

This... (with 'https:')

<link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.12.1/themes/smoothness/jquery-ui.css">
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.12.1/jquery-ui.min.js"></script>

Becomes... ('https:' has been replaced)

<link rel="stylesheet" href="//ajax.googleapis.com/ajax/libs/jqueryui/1.12.1/themes/smoothness/jquery-ui.css">
<script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.12.1/jquery-ui.min.js"></script>

vbence · Accepted Answer · 2011-03-13 14:53:34Z

1

I don't know on how many pages you want this to happen onward the user checks the box, but one answer is JavaScript and the base tag.

With the base tag, you can force a different origin, what your relative URL-s will be resolved against.

I you are using it ina form, and the user ticks the checkbox them sumbits the form, all other pages will be viewed from the https site, so you can use relative URL-s everywhere, just insert a different base tag when the user wants to change the site form or to http(s).

edited Mar 13, 2011 at 14:53

answered Mar 13, 2011 at 12:26

vbence

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Comments

FaZ · Accepted Answer · 2017-12-01 04:27:16Z

1

A solution that doesn't replace urls which contain other urls, for instance http://foo.com/redirect-to/http://newfoo.com

$desiredScheme = "http"; // convert to this scheme;
$parsedRedirectUri = parse_url($myCurrentUrl);
if($parsedRedirectUri['scheme'] !== $desiredScheme) {
    $myCurrentUrl= substr_replace($myCurrentUrl, $desiredScheme, 0, strlen( $parsedRedirectUri['scheme'] ));
}

answered Dec 1, 2017 at 4:27

FaZ

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Comments

Chetan Patel · Accepted Answer · 2014-04-04 15:47:47Z

-1

$count = 1;
$url = str_replace("http://", "https://", $url, $count);

Note : Passing 1 directly will throw fatal error (Fatal error: Only variables can be passed by reference) so you have to pass it last parameter by reference.

answered Apr 4, 2014 at 15:47

Chetan Patel

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1 Comment

Francesco Casula Over a year ago

It throws an error because $count will just contain the number of replacements performed. It's not a parameter meant to set boundaries or anything.

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