I have this code:
str = "text"
x = str.encode('ascii')
print(x)
I got this: b'text'
I want to get this: "116 101 120 116" as string. I want the solution like here I got.
2 Answers
print ([ord(c) for c in 'text'])
# [116, 101, 120, 116]
From docs:
Given a string of length one, return an integer representing the Unicode code point of the character when the argument is a unicode object, or the value of the byte when the argument is an 8-bit string. For example, ord('a') returns the integer 97, ord(u'\u2020') returns 8224. This is the inverse of chr() for 8-bit strings and of unichr() for unicode objects. If a unicode argument is given and Python was built with UCS2 Unicode, then the character’s code point must be in the range [0..65535] inclusive; otherwise the string length is two, and a TypeError will be raised.
Comments
Use map to map each character to its ascii value
str1 = "text"
list(map(ord,str1))
If you need as a string output
str1 = "text"
' '.join(list(map(str,map(ord,str1))))
1 Comment
Relative0
Seems this is faster than the below method by almost a multiple of 2.
print(list(x))gives you the integers.print(*x)would give you space-separated integers.isinstance('anything', str)will not work as expected.