Python function in imported file cannot access another function in the calling Jupyter notebook

Question

I am using Jupyter notebook with python version 3.6. I have some code written in a separate external.py file that I import, then call a function from this file. This function then calls a function defined in the body of the python notebook. For instance,

import external
def subsequent():
    <some code>
external.func1()

func1 is called successfully but gives error when calling 'subsequent', from within func1. I have tried moving the 'import external' line to be after the definition of 'subsequent'. This did not work either.

Is there a way to reference the calling ipython notebook?

Many thanks

Regards,

Adeel

Does func1() calls subsequent() function?

Karthick Aravindan
– Karthick Aravindan

2018-11-01 06:13:29 +00:00
Commented Nov 1, 2018 at 6:13 — Karthick Aravindan
– Karthick Aravindan, Commented Nov 1, 2018 at 6:13

Dulmina · Accepted Answer · 2018-11-01 06:55:38Z

1

Try lambda function and pass that function as a parameter to func1.

  from external import func1
  subsequent=lambda a : print(a + 10)
  func1(subsequent)

OR

pass the function as a parameter

from external import func1
def subsequent(a):
    print(a + 10)
func1(subsequent)

Cheers :-)

edited Nov 1, 2018 at 6:55

answered Nov 1, 2018 at 6:36

Dulmina

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1 Comment

Adeel Hashmi Over a year ago

Thanks a lot, Dulmina. Worked like a charm!

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