I have a model like this:
class Person(models.Model):
name = models.Charfield(max_length¶=30)
photo = models.FileField(upload_to='uploads/')
Is there any way to dynamically change the Storage class of photo field based on the value of the name field?
for example, I want to store the photo of the persons with the name xxx to FileSystemStorage¶ and for the others I want to use S3Storage
I also had a similar use case. Update storage dynamically using the model field object_storage_name.
Tried this below code by taking inspiration from the article https://medium.com/@hiteshgarg14/how-to-dynamically-select-storage-in-django-filefield-bc2e8f5883fd
class MediaDocument(models.Model):
object_storage_name = models.CharField(max_length=255, null=True)
file = DynamicStorageFileField(upload_to=mediadocument_directory_path)
class DynamicStorageFieldFile(FieldFile):
def __init__(self, instance, field, name):
super(DynamicStorageFieldFile, self).__init__(
instance, field, name
)
if instance.object_storage_name == "alibaba OSS":
self.storage = AlibabaStorage()
else:
self.storage = MediaStorage()
class DynamicStorageFileField(models.FileField):
attr_class = DynamicStorageFieldFile
def pre_save(self, model_instance, add):
if model_instance.object_storage_name == "alibaba OSS":
storage = AlibabaStorage()
else:
storage = MediaStorage()
self.storage = storage
model_instance.file.storage = storage
file = super(DynamicStorageFileField, self
).pre_save(model_instance, add)
return file
It worked fine.
Yes, You can assign custom upload location for some specific file.
def my_upload_function(instance, filename):
if instance.name === your_name:
return your_location
return generic_location
class Person(models.Model):
name = models.Charfield(max_length¶=30)
photo = models.FileField(upload_to=my_upload_function)
