How to add all integer from String in sequence?

Question

for Example:

2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26

but i does not get desired results

when i add all char it gives output as: 266

import java.util.Scanner;

public class ProjectEu {
  public static void main(String...rDX) {
    int degree = new Scanner(System.in).nextInt();
    String store = Integer.toString((int)Math.pow(2,degree));
    char [] finals  = store.toCharArray();

    int temp = 0;
    for (int i = 0, n = store.length(); i < n; i++) {
        System.out.printf("values[%d] --> %c \n",i, finals[i]);
        temp = temp + finals[i];
    }

    System.out.println(temp);
 }
}

Pratik Katariya, if my answer helped you can you please mark it as accepted? — Ishaan Javali
– Ishaan Javali, Commented Dec 20, 2018 at 20:13

Ishaan Javali · Accepted Answer · 2018-11-12 14:10:52Z

1

The reason that you are getting this error is because temp is an integer, but finals[i] is a character, so it converts the characters into ASCII values and adds them. You can fix this problem by doing:

for (int i = 0, n = store.length(); i < n; i++) {
    char ch = store.charAt(i);
    int digit = Integer.parseInt(Character.toString(ch));
    temp = temp + digits;
}

answered Nov 12, 2018 at 14:10

Ishaan Javali

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Comments

ETO · Accepted Answer · 2018-11-12 14:16:49Z

0

Try this:

int sum = store.chars()
               .boxed()
               .map(Character::getNumericValue)
               .mapToInt(Integer::intValue)
               .sum();

answered Nov 12, 2018 at 14:16

ETO

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forpas · Accepted Answer · 2018-11-12 14:18:28Z

0

This line:

temp = temp + finals[i];

sums temp and the ASCII code of the char stored in finals[i].
You can get the value of the digit by this:

temp = temp + finals[i] - '0';

This means that by subtracting from the digit's ASCII code the ASCII code of 0 you get the number value of the digit.

edited Nov 12, 2018 at 14:18

answered Nov 12, 2018 at 14:09

forpas

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Comments

Arnaud · Accepted Answer · 2018-11-12 14:23:10Z

0

When you are adding a character to an integer, you are adding the integer code of the character, not its actual numeric value .

What you need is Character.getNumericValue :

temp = temp + Character.getNumericValue(finals[i]);

edited Nov 12, 2018 at 14:23

answered Nov 12, 2018 at 14:10

Arnaud

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