How to initialize List inherits from List C#?

Question

I am new to inherit from list concept and I have a little confusion of initializing that.

Here is a simple example of my real code, here is my class that inherits from list:

public class List_Of_Int : List<int>
{
    public string key{get; set;}
    public List_Of_Int(string key)
    {
        this.key = key;
    }
}

and here is where I need to initialize my variable:

    List<int> list_of_int = new List<int>() { 1, 2, 3 };
    List_Of_Int list_of_list = new List_Of_Int("some_key") **Some Code**

I want to assign list_of_int to my list_of_list, I believe there's a code replace some code that will do that, Is it true?

I know I can add by using AddRange(list_of_int ) later but I'm just wondering if I can do it while declaration?

stackoverflow.com/questions/21692193/why-not-inherit-from-listt — marsze
– marsze, Commented Nov 12, 2018 at 14:13
That code makes no sense. You have a list of entegers and want to initliazie it with a string? Or just add a random property into the new class, with no relations to the list itself? I do agree that it sounds like you should create a class containing a list, rather then inheriting from list. — Christopher
– Christopher, Commented Nov 12, 2018 at 14:14
Look at the other constructors of List. You are missing the one that takes the IEnumerable. — Hans Passant
– Hans Passant, Commented Nov 12, 2018 at 14:16

Rahul · Accepted Answer · 2018-11-12 14:15:10Z

1

Just wondering what you are asking actually but I guess this is what probably you are looking at

public class List_Of_Int
{
    public List<int> key {get; set;}
    public List_Of_Int(List<int> key)
    {
        this.key = key;
    }
}

You can now initialize like

List<int> list_of_int = new List<int>() { 1, 2, 3 };
List_Of_Int list_of_list = new List_Of_Int(list_of_int)

answered Nov 12, 2018 at 14:15

Rahul

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1 Comment

This highlights exactly why you should Prefer composition over inheritance?