I'm using Laravel, and I've a simple nested array
[
['id' => 1, 'name' => 'name1', 'phone' => '0'],
['id' => 2, 'name' => 'name2', 'phone' => '00'],
['id' => 3, 'name' => 'name3', 'phone' => '000']
]
I want to use Laravel array_forget() or any other simple way
to get this array without phones
You could do:
$elements = [
['id' => 1, 'name' => 'name1', 'phone' => '0'],
['id' => 2, 'name' => 'name2', 'phone' => '00'],
['id' => 3, 'name' => 'name3', 'phone' => '000']
];
$elements_without_phones = collect($elements)->map(function ($element){
array_forget($element, 'phone');
return $element;
});
->map() part in the eloquent collection: $elements = Model::where('field', 'value')->get()->map(...);You could take a look at laravel's advanced collection methods - a handy bunch of helpers designed to work with array-like collections in Laravel. What you might need is namely the except() method
You have to iterate the array of arrays, and apply the array_forget() function on every (sub)array.
$array = [
['id' => 1, 'name' => 'name1', 'phone' => '0'],
['id' => 2, 'name' => 'name2', 'phone' => '00'],
['id' => 3, 'name' => 'name3', 'phone' => '000']
];
foreach($array as &$sub_array) { //note the passing by reference
array_forget($sub_array, 'phone');
}
$collection = collect(['product_id' => 1, 'name' => 'Desk', 'price' => 100, 'discount' => false]);
$filtered = $collection->only(['product_id', 'name']);
$filtered->all();
// Output: ['product_id' => 1, 'name' => 'Desk']
toArray() inside the closure but that actually replies to the question. Please edit your answer above accordingly.toArray() would be redundant.