How can I make seaborn distribution subplots in a loop?

Question

I have a 5D array called data

for i in range(10):
     sns.distplot(data[i,0,0,0], hist=False)

But I want to make them inside subplots instead. How can I do it?

Tried this:

plt.rc('figure', figsize=(4, 4))  
fig=plt.figure()
fig, ax = plt.subplots(ncols=4, nrows=3)

for i in range(10):
    ax[i].sns.distplot(data[i,0,0,0], hist=False)
plt.show()

This obviously doesn't work.

ImportanceOfBeingErnest · Accepted Answer · 2018-11-14 23:50:19Z

25

You would want to use the ax argument of the seaborn distplot function to supply an existing axes to it. Looping can be simplified by looping over the flattened array of axes.

fig, axes = plt.subplots(ncols=4, nrows=3)

for i, ax in zip(range(10), axes.flat):
    sns.distplot(data[i,0,0,0], hist=False, ax=ax)
plt.show()

answered Nov 14, 2018 at 23:50

ImportanceOfBeingErnest

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1 Comment

Jia Gao Over a year ago

This way, how can one manage to further modify the subplot like adding the title or axis label, specify sticks etc., etc.

Tim · Accepted Answer · 2018-11-14 23:26:12Z

4

Specify which subplot each distplot should fall on:

f = plt.figure()
for i in range(10):
    f.add_subplot(4, 3, i+1)
    sns.distplot(data[i,0,0,0], hist=False)
plt.show()

answered Nov 14, 2018 at 23:26

Tim

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