Converting curl request to python request

Question

I'm trying to convert the cURL command to python requests, but hitting a wall. Maybe someone will have an idea.

I was using this site for reference and I have such a cURL command:

curl -F "[email protected]" -H "Authorization: ApiKey xxxxxxxxxxx" -F 'scan_type=Arachni Scan' -F 'tags=test' -F 'active=true' -F 'scan_date=2018-11-15' -F 'engagement=/api/v1/engagements/1/'  -F 'eid=1' https://example.com:443/api/v1/importscan/

After the conversion to python, my script extract looks like this:

files = {
    'file': ('myfile.json', open('myfile.json', 'rb')),
    'scan_type': 'Arachni Scan',
    'tags': 'test',
    'active': 'true',
    'scan_date': '2018-11-15',
    'engagement': '/api/v1/engagements/1/',
    'eid': '1',
}

response = requests.post('https://example.com:443/api/v1/importscan/', headers=headers, files=files)
print response.text

Unfortunately, the cURL command succeeds, but the python request returns

{"error": "Request is not valid JSON."}

What am I missing here? Thanks!

Have you tried: (1) using json.dumps(), (2) using a list instead of a tuple for 'file', or (3) doing open(...).read() instead of just open()? — Green Cloak Guy
– Green Cloak Guy, Commented Nov 15, 2018 at 16:02

rbcvl · Accepted Answer · 2018-11-15 16:05:56Z

1

import json

response = requests.post('https://example.com:443/api/v1/importscan/', headers=headers, files=json.dumps(files))

Use json.dumps would do the trick.

answered Nov 15, 2018 at 16:05

rbcvl

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