php time and date function

Question

I have a quickie here, Whenever I try to echo out the time in hours:min:sec using the date() function everything works perfect. But when I try echoing it out using a variable with a value, it always adds up 2 hours.

Take a look at the code:

$time = time();

$past = 120;

//this works perfectly

echo $time = date("H:i:s",$time);

//but this doesnt. it adds 2 hours.

echo $time = date("H:i:s",$time);

miqbal · Accepted Answer · 2011-03-16 23:28:59Z

4

string date ( string $format [, int $timestamp ] )

On second using of "date" function, second param is string. Like that 01:01:01. But it must be integer. So converting 01:01:01 to integer; it will be "0". What's your purpose?

answered Mar 16, 2011 at 23:28

miqbal

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4 Comments

saadlulu Over a year ago

all am trying to do is converting from timestamp to readable format

saadlulu Over a year ago

example: 3600 in timestamp = 01:00:00 in 24 hours system

miqbal Over a year ago

echo date("H:i:s"); // prints now. 01:39:02. echo date("H:i:s", time()); // prints now. 01:39:02. echo date("H:i:s", mktime("01","39","02", "17", "03", "2011")); // prints now. 01:39:02.

saadlulu Over a year ago

great, i got a better understanding of mktime :)

Piotr Salaciak · Accepted Answer · 2011-03-16 23:44:28Z

1

Watch out what You are doing:

//You are assigning a string to $time variable

echo $time = date("H:i:s",$time);

//second call - trying to format date from unix timestamp, which actually is a string with some hours, minutes and seconds

echo $time = date("H:i:s",$time);

EDIT

Maybe You mean this?

$time = time();
$past = 120;
echo date("H:i:s",$time);
echo date("H:i:s",$time - $past);

edited Mar 16, 2011 at 23:44

answered Mar 16, 2011 at 23:32

Piotr Salaciak

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1 Comment

saadlulu Over a year ago

what am trying to do is format date from unix timestamp, that is what am trying to do.

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