I have a list : operation = [5,6] and a dictionary dic = {0: None, 1: None}
And I want to replace each values of dic with the values of operation.
I tried this but it don't seem to run.
operation = [5,6]
for i in oper and val, key in dic.items():
dic_op[key] = operation[i]
Does someone have an idea ?
Other option, maybe:
operation = [5,6]
dic = {0: None, 1: None}
for idx, val in enumerate(operation):
dic[idx] = val
dic #=> {0: 5, 1: 6}
Details for using index here: Accessing the index in 'for' loops?
zip method will do the job
operation = [5, 6]
dic = {0: None, 1: None}
for key, op in zip(dic, operation):
dic[key] = op
print(dic) # {0: 5, 1: 6}
The above solution assumes that dic is ordered in order that element position in operation is align to the keys in the dic.
Using zip in Python 3.7+, you could just do:
operation = [5,6]
dic = {0: None, 1: None}
print(dict(zip(dic, operation)))
# {0: 5, 1: 6}
dic keys are ordered appropriately?
operation order (they may or may not be). At the least it should be noted.
zipmethod.