Go declared and not used logic [duplicate]

Question

Take this incredibly simple example. which shows variable assignment in and out of a block.

On compilation this results in: u declared and not used

var u string
{
    u, err := url.Parse("http://bing.com/search?q=dotnet")
    if err != nil {
        log.Fatal(err)
    }
}
log.Debug(u)

This simulates a logic block during which we might assess several things and set a var to the value we like depending on logic evaluation. How is this possible?

Exactly as is says, the u declared inside the block is not used (the actual error will tell you the exact line). There's no magic here, and the error is probably saving you from a bug in your code. — Mr_Pink
– Mr_Pink, Commented Nov 21, 2018 at 16:55
The short variable declaration will create new u and err variables, because u is not declared in the same block. Redeclaration can only happen if the variable was declared in the same block. — icza
– icza, Commented Nov 21, 2018 at 16:57
Can't believe nobody used the one sentence that clears everything up: u, err := is a declare and assign of both u and err inside a block, masking the var u string declared in a higher scope. — Elias Van Ootegem
– Elias Van Ootegem, Commented Nov 21, 2018 at 17:21

cn0047 · Accepted Answer · 2018-11-21 17:13:40Z

0

Please pay attention that:

u, err := url.Parse("http://bing.com/search?q=dotnet")

in this line of code you have block scoped variable u which is differ from those one which declared in line: var u string, hence you have this error.
Moreover here you have shadowing for variable u from outer block scope which may lead to bugs, see this:

var u string
u = "blank"
{
    u, err := url.Parse("http://bing.com/search?q=dotnet")
    if err != nil {
        log.Fatal(err)
    }
    log.Printf("%#v", u)
}
log.Printf("%#v", u)

Result will be:

2018/11/21 19:12:33 &url.URL{Scheme:"http", Opaque:"", User:(*url.Userinfo)(nil), Host:"bing.com", Path:"/search", RawPath:"", ForceQuery:false, RawQuery:"q=dotnet", Fragment:""}
2018/11/21 19:12:33 "blank"

As you can see here you have even different data types, and variable u not changed after this block.

edited Nov 21, 2018 at 17:13

answered Nov 21, 2018 at 16:59

cn0047

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1 Comment

David Over a year ago

Thanks for the comment. What still seems to escape me a little is how to access the set value of a variable set within a logic block. Take for example a simple - if { u="bob1"}else{ u = "bob2"} log.Printf(u)

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