Bash: capture the echo of a script in a variable

Question

I have script1 which calls script2 which contains an echo statement. I want script1 to send the echo returned by the script2 to a named_pipe. Is there a way to do it without having to change the code of script2? Like "capturing" the echo statements?

SCRIPT1:

...
case ${input_args[0]} in
        SCRIPT2)
            ./SCRIPT2.sh ${input_args[1]};;
...

SCRIPT2:

echo "OK: done!"

Tamás Zahola · Accepted Answer · 2018-11-23 14:32:08Z

2

Just redirect the output to the named pipe:

./SCRIPT2.sh ${input_args[1]} >"my_named_pipe"

Named pipes are just like files in this sense.

answered Nov 23, 2018 at 14:32

Tamás Zahola

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3 Comments

Fabio Magarelli Over a year ago

Thanks Tamas, I did like that but there where other issues in the code which prevented it to work. Now is working fine. The only problem is that if in SCRIPT2 you have multiple echo statement, they are not printed well :(... any tips?

Tamás Zahola Over a year ago

So you want to send the output of SCRIPT2 both to the terminal and the named pipe? In that case you can use tee like this: ./SCRIPT2.sh ${input_args[1]} | tee "my_named_pipe"

Fabio Magarelli Over a year ago

Thank you tamas! :)

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