JS Regex: How to capture repeating pattern into different array elements?

Question

For example, I have a target string like: str='Every "red","white","blue" flower is $7.'

If I run /Every ("(.+)",?)+ flower is \$(.+)/.exec(str), I will get "red","white","blue" as a whole output element, but what I want is ["red,"white","blue"].

Is there a way to do this, or I can only use split?

Thanks!

If the double-quotes are balanced, either lookbehind for " in a global .match while matching non-"s, or repeatedly exec "([^"]+)" and extract the first group — CertainPerformance
– CertainPerformance, Commented Nov 26, 2018 at 3:13

GMaiolo · Accepted Answer · 2018-11-26 04:31:34Z

1

A global parameter RegExp and a String.match() solution would be the most practical:

str.match(/"(.*?)"/g) // [ '"red"', '"white"', '"blue"' ]

answered Nov 26, 2018 at 4:31

GMaiolo

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3 Comments

Romulus Urakagi Ts'ai Over a year ago

Is this able to be modified to also capture other patterns like the tail $7?

GMaiolo Over a year ago

@RomulusUrakagiTs'ai yes doing something like /("(.*?)")|(\$\d+)/g would catch that format as well

Romulus Urakagi Ts'ai Over a year ago

Hmm, this is a bit different from what I want to ask, but I think I can use the combination. Thank you.

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