bash: echo the output of a curl command in pipe

Question

I try to echo the output of curl in a pipe: I tried

curl -s --fail --compressed -u $CREDS -X GET URL | echo * | jq -S "." > file.txt

curl -s --fail --compressed -u $CREDS -X GET URL | echo | jq -S "." > file.txt

curl -s --fail --compressed -u $CREDS -X GET URL | xargs echo | jq -S "." > file.txt

But they all didn't work. What am I doing wrong?

Remove | echo part. Didn't work is not a problem description. Please include example input and example and expected output. — KamilCuk
– KamilCuk, Commented Nov 30, 2018 at 8:47

fancyPants · Accepted Answer · 2018-11-30 08:52:16Z

1

Instead of echo use tee.

curl -s --fail --compressed -u $CREDS -X GET URL | tee - | jq -S "." > file.txt

man page:

NAME tee - read from standard input and write to standard output and files

SYNOPSIS tee [OPTION]... [FILE]...

DESCRIPTION Copy standard input to each FILE, and also to standard output.
   -a, --append
          append to the given FILEs, do not overwrite

   -i, --ignore-interrupts
          ignore interrupt signals

   If a FILE is -, copy again to standard output.

answered Nov 30, 2018 at 8:52

fancyPants

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2 Comments

mealesbia Over a year ago

Thanks, but now I got: parse error: Invalid string: control characters from U+0000 through U+001F must be escaped at line 19, column 3 tee: -: I/O error

chepner Over a year ago

@mealesbia Unless curl ... | jq -S "." fails to raise the same error, that's an unrelated question.

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