Get objects having id in 1st array as same as id in objects of other array in java script

Question

I have 2 arrays of objects. They are

array1 = [{
  id:2,
  name:"person2"
},{
  id:3,
  name:"person3"
},
{
  id:4,
  name:"person4"
},
{
  id:5,
  name:"person5"
},
];
array2 = [
{
    empId:2,
    isdeleted:false
},
{
    empId:4,
    isdeleted:false
}, 
{   
    empId:3,
    isdeleted:true
}];

I need the object from array1 whose id matches with empId of array2 and having isdeleted false. Thanks in advance.

I have attempted it but I didn't get what i expected.Below is the query i have tried. Can u help me with this Roope. this.array1.filter(o => this.array2.find(o2 => o.id === o2.empId)) — roopteja
– roopteja, Commented Dec 4, 2018 at 10:39
Okay, you should include your efforts in the question. The first thing said behind the link is "It appears no attempt was made". Emphasis on "appears". If you do not give any indication of an attempt in your question, others can only assume that you have not attempted anything yourself. — user1425689
– user1425689, Commented Dec 4, 2018 at 10:43

adiga · Accepted Answer · 2018-12-04 10:47:34Z

1

You can use filter and some like this:

let array1 = [{
    id: 2,
    name: "person2"
  }, {
    id: 3,
    name: "person3"
  },
  {
    id: 4,
    name: "person4"
  },
  {
    id: 5,
    name: "person5"
  },
];

let array2 = [{
    empId: 2,
    isdeleted: false
  },
  {
    empId: 4,
    isdeleted: false
  },
  {
    empId: 3,
    isdeleted: true
  }
];

let filteredArray = array1.filter(a => array2.some(b => b.empId === a.id && !b.isdeleted));
console.log(filteredArray);

edited Dec 4, 2018 at 10:47

answered Dec 4, 2018 at 10:40

adiga

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3 Comments

roopteja Over a year ago

One more question is that if in array2 I have age as well. then if i want the resultant object as {id:some_id,name:some_name,age:some_age}. Is that possible?

adiga Over a year ago

You want to filter based on age as well?

roopteja Over a year ago

I have edited the comment. Would you please look into it.

holydragon · Accepted Answer · 2018-12-04 10:37:49Z

0

Try

let result = [];
array1.forEach(function(element1){
    array2.forEach(function(element2){
        if (element1.id === element2.empId && !element2.isdeleted){
            result.push(element);
        }
    });
});
console.log(result);

answered Dec 4, 2018 at 10:37

holydragon

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Comments

Ankit Agarwal · Accepted Answer · 2018-12-04 10:44:25Z

0

You can use Array.filter() together with find() to find the object with that condition in array2:

var array1 = [{
    id: 2,
    name: "person2"
  }, {
    id: 3,
    name: "person3"
  },
  {
    id: 4,
    name: "person4"
  },
  {
    id: 5,
    name: "person5"
  },
];
var array2 = [{
    empId: 2,
    isdeleted: false
  },
  {
    empId: 4,
    isdeleted: false
  },
  {
    empId: 3,
    isdeleted: true
  }
];

var res = array1.filter((obj1)=>{
  var exist = array2.find((obj2)=> (obj1.id == obj2.empId && !obj2.isdeleted));
  return exist;
});
console.log(res);

answered Dec 4, 2018 at 10:44

Ankit Agarwal

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Comments

Terry Lennox · Accepted Answer · 2018-12-04 10:49:08Z

0

You could try something like this:

let array1 = [
    { id:2, name:"person2"},
    { id:3, name:"person3"},
    { id:4, name:"person4"},
    { id:5, name:"person5"}
];
  
let array2 = [
    { empId:2, isdeleted:false},
    { empId:4, isdeleted:false}, 
    { empId:3, isdeleted:true}
];

let result = array1.reduce((output, item) => {
    if (array2.find((item2) => !item2.isdeleted && item.id === item2.empId)) output.push(item);
    return output;
}, []);

console.log(result);

edited Dec 4, 2018 at 10:49

answered Dec 4, 2018 at 10:43

Terry Lennox

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