Check if string contain word in array and break to true php

Question

I use code below to check if comment contains any word in array below. It returns true if detect word.

$blacklist = array("fuck","shit","pussy", "mail.ru","viagra pill", "bitcoin", "конце", "pharmacy", "bad credit","casinos");
function checkblacklist($commnetct) {
  foreach ($blacklist as $word) {
    if (strpos($commnetc, $word) !== FALSE) { 
        return true; 
        break;
    }
  }
}

Then I use

if(checkblacklist($stringcomment)) {

}

Can you help me to check if something wrong because it does not work

Can you elaborate on "does not work"? Are you getting an error? The wrong result? — Mureinik
– Mureinik, Commented Dec 9, 2018 at 8:43
Your parameter is $commnetct and in your check you are using $commnetc. — Nigel Ren
– Nigel Ren, Commented Dec 9, 2018 at 8:46
You also don't need break after the return as it will never get there. — Nigel Ren
– Nigel Ren, Commented Dec 9, 2018 at 8:47

Kamrul Touhid · Accepted Answer · 2018-12-09 09:57:57Z

2

You did not passed parameters in your function

Follow this code

$blacklist = array("fuck","shit","pussy", "mail.ru","viagra pill", "bitcoin", "конце", "pharmacy", "bad credit","casinos");
function checkblacklist($commnetct,$blacklist) {
    foreach ($blacklist as $word) {
        if (strpos($commnetct, $word) !== FALSE) {
            return true;

        }
    }

    return false;
}

$stringcomment = "shit";
if(checkblacklist($stringcomment,$blacklist)) {
    echo "true";
}else{
    echo "false";
}

edited Dec 9, 2018 at 9:57

answered Dec 9, 2018 at 9:32

Kamrul Touhid

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