Maxima plot discrete data with 3 columns

Question

How to plot a discrete dataset with 3 or more columns? MWE is as follows:

/* Required essentially to create the data set */
eqn1: 4 - x^2 - 4*y^2$
eqn2: y^2 - x^2 + 1$
sol: rk([eqn1,eqn2],[x,y],[-1.25, 0.75],[t,0,4,0.2])$

/* My current workaround to plot (x vs t) and (y vs t) */
n : length(sol)$
/* Select the ith column and create separate lists */
tseries : makelist(sol[i][1], i, 1, n)$ 
xseries:  makelist(sol[i][2], i, 1, n)$ 
yseries:  makelist(sol[i][3], i, 1, n)$ 

plot2d([
    [discrete, tseries, xseries],
    [discrete, tseries, yseries]
], [legend,"x","y"] ,[xlabel,"t"], [ylabel,"x, y"],[style, 
[linespoints,2,2]],
[gnuplot_preamble,"set key box width 2 spacing 1.3 top left"])$

Is there a better solution to plot without creating the tseries, xseries and yseries lists?

Well, it seems like [sol[k][2], sol[k][3]] are the x and y coordinates corresponding to sol[k][1]. So maybe plot2d([discrete, map (rest, sol)]) is enough. — Robert Dodier
– Robert Dodier, Commented Dec 11, 2018 at 17:38
@RobertDodier: This doesn't produce the same plots. The command map(rest,sol) produces the 2nd and 3rd column of the original data set. So I am guessing a variation of the above command will give the (1st and 2nd column) and (1st and 3rd column). — ASarkar
– ASarkar, Commented Dec 12, 2018 at 8:48

Robert Dodier · Accepted Answer · 2018-12-12 17:52:08Z

2

OK, based on your comment I see what is the goal. Your solution can be made a little more brief although not a lot. Anyway, map(lambda([txy], [txy[1], txy[2]]), sol) produces the list of [t, x] points and map(lambda([txy], [txy[1], txy[3]]), sol) produces the list of [t, y] points. So with sol as given above, I find that

plot2d ([[discrete, map(lambda([txy], [txy[1], txy[2]]), sol)],
         [discrete, map(lambda([txy], [txy[1], txy[3]]), sol)]]);

has the desired output (omitting the plotting options for clarity).

answered Dec 12, 2018 at 17:52

Robert Dodier

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