Can someone explain why this program is printing "v" as output? I understand that the commented part of the code is used to access the 3rd char of the 2nd string, but how does the first one work?
#include<stdio.h> int main(void) { static char a[3][5] = {"axcd", "efgh","ijkl"}; putchar (*(*a+1)-2); // putchar (*(*(a+1))+2); }
Generally you should initialize a 2D array by double brackets, i.e
static char arr[2][3] = {{"a","b","c"},{"e","f","g"}};
To access, for example, "g" which is in the second row and third column we use:
*(arr + (1 * 3 + 2));
'arr' is address in the memory where the array is stored. '1' is the index of the wanted row, '3' is the length of each row (==number of columns). '2' is the index of the element we want in the appropriate row.
In the general case to get an element in row i and column j we use:
int arr[N][M], i, j;
... //set values for i, j..
*(arr + (i*M + j));
