List index out of range error with Python 3

Question

for x in range (0,24):
  RandCharGen = random.randint(0,len(characters)) 
  RandChar = characters[RandCharGen]

Shows the error:

RandChar = characters[RandCharGen]
IndexError: list index out of range

Does anyone have the solution?

Quick remark: name your variables by PEP8 standard like snake_case: en.wikipedia.org/wiki/Snake_case. — andreihondrari
– andreihondrari, Commented Dec 15, 2018 at 17:39
randint returns numbers including the second value, which results in an out-of-bounds access. — Norrius
– Norrius, Commented Dec 15, 2018 at 17:40

Jean-François Fabre · Accepted Answer · 2018-12-15 17:46:57Z

1

as explained in comments, you can get out of bounds for your string, unless you use random.randrange, which was added to avoid this issue (which can be stealthy because of the random aspect). More about this: Difference between random randint vs randrange

But a better solution would be random.choice to pick a random item from your string/list:

for x in range (0,24):
  RandChar = random.choice(characters)

answered Dec 15, 2018 at 17:46

Jean-François Fabre♦

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Comments

Picachieu · Accepted Answer · 2018-12-15 17:48:04Z

1

The randint function returns a value including both end points. If characters was 10 characters long, the highest number it could return is 10, which would be higher than the highest index, 9. You can change it to this:

for x in range (0,24):
    RandCharGen = random.randint(0,len(characters)-1) 
    RandChar = characters[RandCharGen]

or this:

for x in range (0,24):
    RandChar = random.choice(characters)

answered Dec 15, 2018 at 17:48

Picachieu

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