How to have a variable action?

Question

Writing with MVC in C#, I have a device that issues an HTTP request to {host}/clock. I want different devices to write to different places, so I want to enter the host as {.../company1/}, {.../company2/}. I would then have a CompanyController that would redirect requests for company1, company2, etc. without hardcoding the names of the companies.

So a request to {host}/company/company1/clock would write to company1's database. Presumably if I entered {host}/company/notacompany/, I would still want to see the value "notacompany", so I can redirect it somewhere else. How would I go about catching company1 as an address within the company controller without specifically coding a company1 action, or is this the wrong way to go about this?

Racil Hilan · Accepted Answer · 2018-12-21 21:58:34Z

3

You can use attribute routes to tell the routing engine what to do with the route parameter (company1, company2, etc...). You can use a switch and handle the notacompany in the default:

public class CompanyController : Controller {
    [Route("/[controller]/{companyId}")]
    public ActionResult Index(string companyId) {
        switch(companyId) {
            case "company1":
                //Process company1.
            case "company2":
                //Process company2.
            default:
                //Process 'notacompany' here.
        }
    }
}

answered Dec 21, 2018 at 21:58

Racil Hilan

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4 Comments

Ryan D. Over a year ago

I appreciate the reply, unfortunately this doesn't solve my issue. I would still have to hard code each case for every new company I add.

Racil Hilan Over a year ago

How else do you expect the app to know where to redirect the request? Somewhere, you'll have to tell it what do and where to go. You don't need to hardcode the values in the switch statement. I only did that for the answer, but you can have the list of companies coming from a database, an xml fine, the config fine, etc...

Racil Hilan Over a year ago

Correction: (an xml file, the config file)

Ryan D. Over a year ago

Ah yes I could do that, thanks for the clarification

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