Parsing JSON array values

Question

I faced with the problem while trying parse JSON array and list all values it has, I have the following JSON format

{
  "sdd": {
        "token":"1",
        "details":[{
              "type":"SOME_TYPE",
              "l":,
              "expiration_date":"12\/2020",
              "default":true,
              "expired":false,
              "token":"1"
         }]
   }
 }

JSON output I have

public void onResponse(JSONObject response) {
    try {
        JSONArray ja = response.getJSONArray("ssd");
        for (int i = 0; i < ja.length(); i++) {
            JSONObject jobj = ja.getJSONObject(i);
            Log.e(TAG, "response" + jobj.getString("token"));
            Log.e(TAG, "response" + jobj.getString("details"));
        }
    } catch(Exception e) { e.printStackTrace(); }
}

and in the log cat I getting org.json.JSONException: No value for ssd this output

its not a valid json. Please update your right Json.

Mehul Kabaria
– Mehul Kabaria

2018-12-24 17:59:57 +00:00
Commented Dec 24, 2018 at 17:59 — Mehul Kabaria
– Mehul Kabaria, Commented Dec 24, 2018 at 17:59
your json file is error(line 6), check him !

hamid
– hamid

2018-12-24 18:17:12 +00:00
Commented Dec 24, 2018 at 18:17 — hamid
– hamid, Commented Dec 24, 2018 at 18:17
You could use gson to automatically parse json data.

ali73
– ali73

2018-12-24 18:48:18 +00:00
Commented Dec 24, 2018 at 18:48 — ali73
– ali73, Commented Dec 24, 2018 at 18:48

Axbor Axrorov · Accepted Answer · 2018-12-24 18:27:06Z

4

You have typo. Not ssd but sdd. And also sdd is not array, but object. So you must write like:

JSONObject jb = response.getJSONObject("sdd");

Full parsing code will be like:

public void onResponse(JSONObject response) {
    try {
        JSONObject sdd = response.getJSONObject("sdd");
        JSONArray details = sdd.getJSONArray("details");
        for (int i = 0; i < details.length(); i++) {
            JSONObject jobj = details.getJSONObject(i);
            Log.e(TAG, "response-type:" + jobj.getString("type"));
            Log.e(TAG, "response-token:" + jobj.getString("token"));
            Log.e(TAG, "response-expiration_date:" + jobj.getString("expiration_date"));
            Log.e(TAG, "response-default:" + jobj.getBoolean("default"));
            Log.e(TAG, "response-expired:" + jobj.getBoolean("expired"));
        }
    } catch(Exception e) { e.printStackTrace(); }
}

Also, let me suggest you to use gson this library will help you deserialize your json representations.

edited Dec 24, 2018 at 18:27

answered Dec 24, 2018 at 18:02

Axbor Axrorov

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2 Comments

Stakerrrr Over a year ago

hold on let me try it

Axbor Axrorov Over a year ago

@Stakerrrr if you solve your problem with my answer, you must mark it as Accepted.

sirnino · Accepted Answer · 2018-12-24 18:04:40Z

1

ssd is an object. You can get the array as follows:

JSONObject jo = response.getJSONObject("sdd");
JSONArray ja = jo.getJSONArray("details");

edited Dec 24, 2018 at 18:04

answered Dec 24, 2018 at 18:00

sirnino

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2 Comments

sirnino Over a year ago

Note also that the JSON you are trying to parse is not valid.

sirnino Over a year ago

Before you had "no value for ssd" and now "no value for token". Right? Try to fix the JSON and update the request, please.

hamid · Accepted Answer · 2018-12-24 18:44:48Z

-1

hi you must json file isn't create is create :

{ "sdd":{ "token":"1", "details":[ { "type":"SOME_TYPE", "expiration_date":"12/2020", "default":true, "expired":false, "token":"1" } ] } }

after you can get data from code :

public void onResponse(JSONObject response) {
    try {
        JSONObject ssd = response.getJSONObject("ssd");
        JSONArray details = ssd.getJSONArray("details");
        for (int i = 0; i < details.length(); i++) {
            JSONObject obj = details.getJSONObject(i);
            Log.e(TAG, "response" + obj.getString("type"));
            Log.e(TAG, "response" + obj.getString("expiration_date"));
            Log.e(TAG, "response" + obj.getBoolean("default"));
            Log.e(TAG, "response" + obj.getBoolean("expired"));
            Log.e(TAG, "response" + obj.getString("details"));

        }
    }catch (Exception e){e.printStackTrace();}
}

edited Dec 24, 2018 at 18:44

answered Dec 24, 2018 at 18:16

hamid

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3 Comments

Axbor Axrorov Over a year ago

there is typo, it will gave same error, in json representation wroted sdd but in code wroted like ssd

Stakerrrr Over a year ago

@AxborAxrorov my mistake sorry, I can tick your answer as correct if you want

hamid Over a year ago

@Stakerrrr oh ! is so bad , you first test my code and solved your problem ,So the best answer is my answer . please tick my answer thanks.

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