Checking a string in user input using if statement always end up returning the same output. How can it be fixed?

Question

I'm trying to get the user input and check whether it has 'heads' or 'tails' in it using if statement. But I end up getting the same output.

user_input = input('Heads? or Tails? \n')

if 'HEADS' or 'TAILS' in user_input.upper():
    print ('you have chosen', user_input)
else:
    print ('wrong!')

Input:

random text

Expected output:

wrong!

Output that I get:

you have chosen random text

Even though this is a simple and common misconception, given that you asked it in a good way (with MCVE provided), I go +1 for this — iBug
– iBug, Commented Dec 25, 2018 at 2:21

iBug · Accepted Answer · 2018-12-25 02:20:04Z

2

or does not work that way

if 'HEADS' in user_input.upper() or 'TAILS' in user_input.upper():

answered Dec 25, 2018 at 2:20

iBug

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Comments

Cat_Enthusiast · Accepted Answer · 2018-12-25 02:30:14Z

0

When using the OR operator, you have to treat the latter expression as it's own condition to satisfy:

if "HEADS" in user_input.upper() or "TAILS" in user_input.upper():
  print("you have chosen", user_input)
else:
  print("wrong")

answered Dec 25, 2018 at 2:30

Cat_Enthusiast

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