Android SaxParser XMLReader.parse() and InputSource parameter

Question

I am trying to parse my xml file resource with SaxParser. I have created my DataHandler but I don't know how indicate to XmlReader the location of data.xml that is in res/xml/.

What is the correct parameter for InputSource object?

    XmlResourceParser parser = getResources().getXml(R.xml.data);       
    SAXParserFactory spf = SAXParserFactory.newInstance();
    SAXParser sp = spf.newSAXParser();
    XMLReader xr = sp.getXMLReader();

    // Create handler to handle XML Tags ( extends DefaultHandler ) 
    DataSaxHandler myXMLHandler = new DataSaxHandler();
    xr.setContentHandler(myXMLHandler);
    //R.xml.data is my xml file
InputSource is=new InputSource(getResources().getXml(R.xml.data));  //getResources... is wrong say Eclipse

    xr.parse(is);

Thanks a lot.

Sorry solved.....stackoverflow.com/questions/4680543/…

michele
– michele

2011-03-22 15:26:02 +00:00
Commented Mar 22, 2011 at 15:26 — michele
– michele, Commented Mar 22, 2011 at 15:26

Brian Cooley · Accepted Answer · 2011-03-22 15:35:20Z

1

The problem is that the call to getResources().getXml(int id) is returning a XmlResourceParser, and there is no InputSource constructor that takes an XmlResourceParser.

If you want to stick with the SaxParser, you'll need to open up an InputStream via Resources#openRawResource(int id), and then pass that to the InputSource constructor. You'll also need to move the file to res/raw to use the openRawResource function.

edited Mar 22, 2011 at 15:35

answered Mar 22, 2011 at 15:29

Brian Cooley

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